-56x+20=-15x^2

Solution for -56x+20=-15x^2 equation:

-56x+20=-15x^2

We move all terms to the left:

-56x+20-(-15x^2)=0

We get rid of parentheses

15x^2-56x+20=0

a = 15; b = -56; c = +20;
Δ = b2-4ac
Δ = -562-4·15·20
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-44}{2*15}=\frac{12}{30}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+44}{2*15}=\frac{100}{30}
=3+1/3
$